Physics, asked by vivekcharles8474, 6 hours ago

the time taken by the ball to reach the point of maximum height above its point of projection equal.(a)u sin thita/g(b) u g sin thita (c)g sin thita/u(d)gu/sin thita

Answers

Answered by simabhattacharyya69

0

Answer:

s= it+ 1/2 at²

Explanation:

Use this formula

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