Question

The time taken for effusion of 32ml of oxygen will be the same as the time taken for offusion under
identical conditions of
(A) 64 ml of 172
(B) 50 mL of NA
(C) 27.3 mL of CO,
(D) 22.62 ml. of SO,​​

Answer 1

solution : according to Graham's law of effusion of gas

rate of effusion of a gas is inversely proportional to square root of its molecular weight. i.e., r ∝ 1/√M

for oxygen gas,

r ∝ 1/√(32)

⇒32/t = k/√(32) , where k is proportionality constant.

⇒kt = 32√(32) ≈ 181 ......(1)

let's check options,

(A) 64/t = k/√(2) ⇒kt = 64√2 = 90.5

(B) 50/t = k/√(28) ⇒kt = 50√28 = 264.57

(C) 27.3/t = k/√(44) ⇒kt = 27.3√(44) = 182

(D) 22.6/t = k/√(64) ⇒kt = 22.62√64 = 181

Answer 2

Answer:

hmmmmmmm........

Step-by-step explanation:

idk