Question

the time velocity graph of a car is shown in the figure calculate acceleration from A to B distance travelled in the last 4 second​

Answer 1

plzz mark as brainiest and say thanks if it helped u

Answer:

a=3m/s^2

distance travelled=6m

Explanation:

given

u=5

v=2

t=1

a=v-u/t

=2-5/1

=-3m/s^2

distance travelled in the last 4 seconds

=area under the graph

=2×2+1/2×2×2

=4+2

=6m