Question

The timeperiodofasimplependulumis2πsec. and accelerationduetogravityisoneforthof thevalueonthesurfaceoftheearth.Calculate the effective length of the pendulum.​

Answer 1

Answer:

The effective length of the pendulum is 2.45m

Explanation:

We know that for a simple pendulum, T = 2π$\sqrt{\frac{L}{g} }$

where, T = Time period of the pendulum

            L = Length of the pendulum

            g = acceleration due to gravity

Substituting the values,

2π = 2π $\sqrt{\frac{L}{\frac{g}{4} }}$

Squaring both sides,

=> 1 = $\frac{4L}{9.8}$

=> 9.8 = 4L

=> L = 9.8/4

=> L = 2.45m

Therefore, the effective length of the pendulum is 2.45m