Question

The tip of a drawing pin has an area 5mm^2. Find the pressure exerted if force applied is 10N

Answer 1

Answer:

P= 200,000 Pa

Explanation:

P = F/A

(5mm^2 = 5 / 1,000,000 m ^2 )

P = (10 x 1,000,000 ) / 5

P  = 2,000,000 N/m^2  or pascals

   = 2 x 10^6 Pa

Answer 2

$\huge\mathfrak\blue{Answer:}$

Pressure:

• Pressure is the perpendicular force exerted by an object per unit area of contact.
• $pressure = \frac{force}{area}$ - - - - - ( 1 )

Given:

• Area of tip of drawing pin = 5 mm²
• Force exerted by Pin on surface = 10 N

To Find:

• The Force exerted by tip of the drawing pin on the surface.

Solution:

Area of Tip of Pin = 5 ${mm}^{2}$

Converting the area into SI unit.

Area = $\frac{5}{ {1000}^{2} } {m}^{2}$

Area = $\frac{5}{ {10}^{6} } {m}^{2}$

Area = $5. {10}^{ - 6} {m}^{2}$

Using Formula of Pressure from equation ( 1 )

Pressure = Force / Area

P = $\frac{10}{5. {10}^{ - 6} }$

Pressure = $2. {10}^{6}$ Pa

Hence pressure excreted by Tip of drawing pin on the surface is $2. {10}^{6}$ Pa