Question

the tip of a drawing pin has an area of 0.01 mm². Find the pressure exerted by it if a force of 20 N is applied by it.​

Answer 1

Explanation:

Area = 0.01 mm² = 1×10^-2 mm² = 1×10^-5

= 1×10^-5 m²

Force = 20 N

We know that,

Pressure = Force / Area

==> 20 / 1 × 10^-5m

==> 20×10^5 Pascal

Thus, the Pressure acting on the given area is 20 × 10^5 Pa

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