Physics, asked by pb408021, 3 days ago

the tip of a drawing pin has an area of 0.01 mm² Find the pressure exerted by it if a force of 20N is applied by it​

Answers

Answered by yashvora1804
2

Answer:

It is given that the tip of the drawing pin has an area of 0.01mm2.

Converting the unit into standard form we get,

Area =0.01mm2=0.011000×1000m2=1100000000m2

According to the given question,

Force applied by the drawing pin is,

Force =20N

Pressure is explained as the force which is applied perpendicular to the surface of an object per unit area over which that force is distributed. In other words, when a force of ‘F’ Newton is applied perpendicularly to a surface of area ‘A’, then the pressure exerted on the surface by the force is equal to the ratio of ‘F’ to ‘A’. The SI unit of pressure is expressed in Pascal (Pa). One pascal is defined as the force of one newton applied over a surface area of a one-meter square.

Mathematically it is given as,

Pressure =ForceArea

Pressure =20(1100000000)=2000000000pascal

∴Pressure=2×109Pa

Hence, the pressure exerted by the drawing pin is 2×109Pa.

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Answered by sonijhahw
2

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