Question

The tip of the drawing pin has an area of 0.1 meter square. Find the pressure exerted by it if a force of 30N is applied by it.

3000N/m2

30N/m2

300N/m2

0.30N/m2

​

Answer 1

Answer:

Option C (300 N/m²)

Explanation:

As per the provided information in the given question, we have :

• Surface area (A) = 0.1 m²
• Force applied (F) = 30 N

We are asked to calculate pressure exerted (P).

As we know that,

$\longmapsto\bf { P = \dfrac{F}{A} }$

• P denotes pressure
• F denotes force
• A denotes area

$\longmapsto\rm { P = \dfrac{30 \; N}{0.1\; m^2} }$

$\longmapsto\rm { P = \dfrac{300 \; N}{1\; m^2} }$

$\longmapsto\rm { P = 300 \; N.m^{-2} }$

$\longmapsto\bf { P = 300 \; Pa}$

Therefore, pressure exerted is 300 Pa or 300 N/m².

$\rule{200}2$

More Information :

• Pressure is defined as force per unit area.
• Its SI unit is N/m² or Pa.
• Pa denotes Pascal.
• When area is more pressure is less.
• When area is less pressure is more.

Answer 2

Answer:-

• Force=30N
• Area=0.1m^2

we know that

$\boxed{\sf Pressure=\dfrac{Force}{Area}}$

$\\ \sf\longmapsto Pressure=\dfrac{30N}{0.1m^2}$

$\\ \sf\longmapsto Pressure=30\times 10N/m^2$

$\\ \sf\longmapsto Pressure=300N/m^2$

$\\ \sf\longmapsto Pressure=300Pa$