Question

the to register are expressed as r1=(4+-0.5),r3=(12+-0.5)what is the not reastance when they are connect in seres and in parral​

Answer 1

Answer:

R=R  

1

​

+R  

2

​

=4+12=16Ω

R  

1

​

=4±(0.5 % of 4) Ω

R  

2

​

=12±(0.5 % of 12) Ω

Errors will be added

R=(R  

1

​

+R  

2

​

)+ΔR  

1

​

+ΔR  

2

​

 

   =16±(0.5 % of 4)+(0.5 % of 12)

   =16±(0.5 % of 16)

R=16±0.5 % Ω