Question

The top five test scores in Mr. Rhodes class were: 98, 92, 96, 97, and 97. What is the mean absolute deviation?

Answer 1

Answer:

average distance between each data point and the mean.

Step-by-step explanation:first find the mean of data set,find sum data value and divide the sum by the number of data of data values. find the difference between each data value and the mean

Answer 2

Answer:

   The mean absolute deviation = 1.6

Step-by-step explanation:

Given data

The top five test scores in Mr. Rhodes class were: 98, 92, 96, 97, 97

here we need to find the mean absolute deviation

the formula for the mean absolute deviation = ∑ | x$_{i}$ - x| / n

here |x$_{i}$ - x| = deviation for given data

         n = number of observations

first of all calculate the mean of the given data

   mean (x) = $\frac{ 98 + 92 + 96 + 97 + 97 }{5}$ = 96

now calculate the mean deviations as shown in below

      scores (x$_{i}$)         deviations ( |x$_{i}$ - x| )

           98                  | 98 -96 | = 2  

           92                  | 92 - 96| = 4

           96                  | 96 - 96| = 0

           97                  | 97 - 96| = 1  

           97                  | 97 - 96| = 1

      ∴  the mean absolute deviation = (2+4+0+1+1) / 5 = 8/5 = 1.6