Question

The top of a broken tree touches the ground at a distance of 12 m from its base. If the tree is broken at a height of 5 m from the ground then the actual height of the tree is-​ .
proper answer I want ​

Answer 1

$\huge\mathfrak\green{Answer}$

Here we go

$\large\mathfrak\pink{ {Ac}^{2} = {Bc}^{2} + {Ab}^{2} }$

$\large\mathfrak\pink{ {Ac}^{2} = ( {5m}^{2}) + ( {12m}^{2})}$

$\large\mathfrak\pink{Ac=25m²+144m² \: = 169m²}$

For founding how we know

which number .is that

For that lets go

$\large\mathfrak\pink{we \:know \: that \: 13 \times 13 = 169}$

$\large\mathfrak\pink{So \:Ac+ Cb=13+5 =18 m}$

Hence the length of tree is 18 m