Question

the top of a ladder of length 15m reaches a window 9m above the ground is the distance between the base of the wall and that of the ladder?​

Answer 1

Given:

• The top of a ladder of length 15m reaches a window 9m above the ground.

To find:

• The distance b/w the base of the wall and that of the ladder.

Solution:

❐ From the figure, we can see,

• The wall and the ground are perpendicular to each other.

• Hence, the ladder leaning against the wall forms a right-angled triangle.

• In ∆ABC, ∠B = 90°

By using Pythagoras theorem,

⇒ (AC)² = (AB)² + (BC)²

⇒ (15)² = (9)² + (BC)²

⇒ 225 = 81 + (BC)²

⇒ 225 - 81 = (BC)²

⇒ 144 = (BC)²

⇒ (12)² = (BC)²

⇒ BC = 12m

Hence, the distance between the base of the wall and that of the ladder is 12m.

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