The top of ladder of length 17 m reaches a window 8 m above the ground. What is the distance the base of the wall and that of the ladder?
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Step-by-step explanation:
AB= distance of window from the ground
AC=length of the ladder
now by applying Pythagoras theorem we get
AC²=AB²+BC²
OR BC²=AC²-AB²
OR BC²=17²-8²=289-64=225
OR BC=√225
OR BC=15
So, the distance between the base of the wall and the ladder is 15 m
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