Question

The top of ladderof lengh 15m is reaching window 9m above the ground .what is the distance between the base of wall and that of ladder​

Answer 1

Step-by-step explanation:

Let LN be the ladder of length 15 m that is resting against a wall. Let M be the base of the wall and L be the position of the window.

The window is 9 m above the ground. Now, MN is the distance between the base of the wall and that of the ladder.

In the right-angled triangle LMN, ∠M = 90°. Hence, side LN is the hypotenuse.

According to Pythagoras' theorem,

l(LN)2 = l(MN)2 + l(LM)2

⇒ (15)2 = l(MN)2 + (9)2

⇒ 225 = l(MN)2 + 81

⇒ l(MN)2 = 225 − 81

⇒ l(MN)2 = 144

⇒ l(MN)2 = (12)2

⇒ l(MN) = 12

∴ Length of seg MN = 16 m.

Hence, the distance between the base of the wall and that of the ladder is 12 m.