Question

the top of the ladder 53 long when placed against a wall reaches a height of 45 metres how far is the foot of the ladder from the wall

Answer 1

Answer:

28 metres

Step-by-step explanation:

Just by using the Pythagoras Theorm

take the ladder's height as 53 m

and the wall till which the ladder rests 45 m

then just calculations

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Distance\:between\:wall\:and\:foot\:of\:ladder=28\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about the top of the ladder 53 long when placed against a wall reaches a height of 45 metres.

• We have to find how far is the foot of the ladder from the wall?

$\green{\underline \bold{Given :}} \\ : \implies \text{Length\:of\:ladder=53\:m} \\ \\ : \implies \text{Height\:of\:wall=45\:m}\\\\ \red{\underline \bold{To \: Find:}} \\ : \implies \text{Distance\:between\:wall\:and\:foot\:of\:wall= ?}$

• Accroding to given question :

$\bold{ By \: pythagoras \: theorem} \\ : \implies {h}^{2} = {p}^{2} + {b}^{2} \\ \\ : \implies {AC}^{2} = {AB}^{2} + {BC}^{2} \\ \\ : \implies {53}^{2} = {45}^{2} + BC^{2} \\ \\ : \implies 2809 = 2025 + {BC}^{2} \\ \\ : \implies 2809 - 2025 = {BC}^{2} \\ \\ : \implies {BC}^{2} = 784 \\ \\ : \implies BC= \sqrt{784} \\ \\ \green{: \implies \text{BC = 28 \: m}}$