the top of two towers of height x and y standing on level ground subtend angles of 30 and 60 respectively at the centre of the loin joining their feet then find x:y
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Answered by
15
Hi,
Draw a rough diagram ,
according to the problem
given ,
|D
I
I IA
I.x y I
I. I
I l
C_______•________B
d. P. d
Join the points D , A to P.
CP = PB = d units
i ) height of the one tower
CD = x units
Angle
In triangle DPC,
Tan 30° = DC / CP
1/√3 = x / d ----( 1 )
ii) Height of the second tower
AB = y units
In triangle APB,
Tan 60° = AB / PB
√3 = y / d ------( 2 )
Find the ratio of ( 1 ) / ( 2 ) ,
(1 / √3)/ (√3 / 1 ) = ( x /d) / ( y / d )
( 1 / √3 )( 1 / √3 ) = x / y
1 / 3 = x / y
Therefore ,
x : y = 1 : 3
I hope this helps you.
:)
Draw a rough diagram ,
according to the problem
given ,
|D
I
I IA
I.x y I
I. I
I l
C_______•________B
d. P. d
Join the points D , A to P.
CP = PB = d units
i ) height of the one tower
CD = x units
Angle
In triangle DPC,
Tan 30° = DC / CP
1/√3 = x / d ----( 1 )
ii) Height of the second tower
AB = y units
In triangle APB,
Tan 60° = AB / PB
√3 = y / d ------( 2 )
Find the ratio of ( 1 ) / ( 2 ) ,
(1 / √3)/ (√3 / 1 ) = ( x /d) / ( y / d )
( 1 / √3 )( 1 / √3 ) = x / y
1 / 3 = x / y
Therefore ,
x : y = 1 : 3
I hope this helps you.
:)
Answered by
20
Hey here's your answer.....
Hope it helps
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