Math, asked by AdibMahrus, 11 months ago

The top point of the graph of the quadratic function y = -3x² - 12x + 5

Answers

Answered by NailanIca
1

y = -3x ^ - 12x + 5

Symmetry axis

x = -b / 2a

x = 12 / -6

x = -2

y = -3 (-2) ^ - 12 (-2) + 5

y = -12 + 24 + 5

y = 17

High point

P (-2, 17)

Or

y = a (x - xp) ^ + yp

y = -3x ^ - 12x + 5

y = -3 (x ^ + 4x) + 5

y = -3 (x + 2) ^ + 17

P (-2, 17)

Similar questions