the tops of two poles of heights 18m and 12m are connected by are connected by a wire. if the wire makes an angle 30 with horizontal, then the length of wire____
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Answer:
12 m
Step By Step Explanation:
Given:
First Pole's Height = AB = 18 m
Second Pole's Height = CD = 12 m
Length of the wire = AD
From The Condition:
AE = AB - BE
⇒ AB - CD
⇒ 18 - 12
⇒ 6 m
Hence, Length Of AE is 6 m.
Now,
In ∆ AED ,
∠ AED = 90° ,
∠ ADE = 30° [ Given ]
We have,
Sin 30° = AE/AD
⇒ 1/2 = 6/AD
⇒ AD = 6 × 2
⇒ AD = 12 m
Hence, The Required length of the wire is 12 m.
12 m
Step By Step Explanation:
Given:
First Pole's Height = AB = 18 m
Second Pole's Height = CD = 12 m
Length of the wire = AD
From The Condition:
AE = AB - BE
⇒ AB - CD
⇒ 18 - 12
⇒ 6 m
Hence, Length Of AE is 6 m.
Now,
In ∆ AED ,
∠ AED = 90° ,
∠ ADE = 30° [ Given ]
We have,
Sin 30° = AE/AD
⇒ 1/2 = 6/AD
⇒ AD = 6 × 2
⇒ AD = 12 m
Hence, The Required length of the wire is 12 m.
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