Physics, asked by sujal8369, 3 months ago

The torque developed by an airplane engine whose
output is 2000 HP at an angular speed of 2400
rev/min. is about
(1) 5937 Nm
(2) 1937 Nm
(3) 2033 Nm
(4) 4189 Nm

Answers

Answered by siddiqa35

1

Answer:

the correct answer is a

Explanation:

w = 2π

2× 2400 ÷60

80π rad/s

power = Torque × angular frequency

2000 × 746 ÷ 80π

= 5937

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