Question

The torque of a force f=-2i+2j+3k acting on a point r=i-2j+k

Answer 1

Use determinants to find the cross product of 2 vectors.

Answer 2

Answer:

$\tau=-8i-5j-2k$

Explanation:

It is given that,

Force acting on the particle, $F=-2i+2j+3k$

Distance from the particle, $r=i-2j+k$

The formula of torque acting on a particle is given by :

$\tau=r\times F$

$\tau=(i-2j+k)\times (-2i+2j+3k)$

$\tau=-8i-5j-2k$

So, the torque acting on the particle is $-8i-5j-2k$. Hence, this is the required solution.