Question

The torque of a force f=-2i+2j+3k acting on a point r=i-2j+k about origin will be

Answer 1

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Answer 2

The torque acting on the object about the origin is $(8i+5j+2k)\ N-m$.

Explanation:

Given that,

Force acting on the object, $F=(-2i+2j+3k)\ N$

Position of the object, $r=(i-2j+k)\ m$

We need to find the torque acting the object. It is given by the cross product of force and displacement. It is given by :

$\tau=F\times r$

$\tau=(-2i+2j+3k)\times (i-2j+k)$

Using the cross product of force and position, it is given by :

$\tau=\begin{pmatrix}8&5&2\end{pmatrix}$

$\tau=(8i+5j+2k)\ N-m$

So, the torque acting on the object about the origin is $(8i+5j+2k)\ N-m$. Hence, this is the required solution.

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