Question

the torque of a force of 50n is 5n. what is the distance​

Answer 1

Given that moment of force is 5 N-m about a point O when we apply a force of 10 N. We know that moment of force is given by formula rXF.

5=r×10

r=0.5m.

Hence we apply a force at a perpendicular distance of 0.5 m.

Answer 2

Answer:

0.1

Explanation:

TORQUE = FORCE * DISTANCE

5n = 50n * DISTANCE

DISTANCE = 5n/50n

DISTANCE = 1/10

DISTANCE = 0.1