Physics, asked by scriptesshutterbug, 4 months ago


The torque of force F=(6i-2j+3k) acting on ongin about the point with position vector (2i +3j)m has a magnitude

Answers

Answered by ashokumar7000
0

Answer:

7

Explanation:

✓6^2 + 2^2+ 3^2 and after solving you can get the answer

Answered by rishikeshm1912
1

Given:

The torque of force F=(6i-2j+3k) acting on origin about the point with position vector (2i +3j)m.

To Find:

Magnitude of torque

Solution:

Given, Force acting on the body =  F=(6i-2j+3k)

And position vector, r = (2i +3j)

Therefore, torque = F.r = [6*2+(-2) *3+  3*0] = [12-6 ] = 6 N-m

Torque is 6 N-m

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