The torque of force F=(6i-2j+3k) acting on ongin about the point with position vector (2i +3j)m has a magnitude
Answers
Answered by
0
Answer:
7
Explanation:
✓6^2 + 2^2+ 3^2 and after solving you can get the answer
Answered by
1
Given:
The torque of force F=(6i-2j+3k) acting on origin about the point with position vector (2i +3j)m.
To Find:
Magnitude of torque
Solution:
Given, Force acting on the body = F=(6i-2j+3k)
And position vector, r = (2i +3j)
Therefore, torque = F.r = N-m
Torque is 6 N-m
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