Question

the torque required to keep a magnet of length 20cm at 30 degrees to uniform magnetic field is 2*10^-5 Nm. the magnetic force on each pole is

Answer 1

Answer:

Explanation:

Torque= Magnetic dipole moment* Magnetic Field* sin θ

            =µ*B*sinθ

            =m*2a*B*sinθ

2*10^-5=m*0.2*B*sin30°

2*10^-4=m*B...(i)

We know  that,

F=B/m...(ii)

This is as far as I've been able to proceed. I feel like there's a quantity I'm missing.  

I apologize for being unable to post the whole answer.

Answer 2

Answer:

Torque =

$2 \times 10 { }^{ - 4}$