the total age of father and son is 80 years.10 years before the age of father was twice to the age of son...what is the present age of those?( solve without putting x)
Answers
Answered by
4
x+y=80 (1)
before 10 years,
x-10=2(y-10)
eliminating
father's age=50
son's age=30
before 10 years,
x-10=2(y-10)
eliminating
father's age=50
son's age=30
Similar questions
Social Sciences,
7 months ago
Social Sciences,
7 months ago
Computer Science,
7 months ago
Art,
1 year ago
Science,
1 year ago