Question

The total ages of three persons a, b, c is 90yrs, 10 yrs before ratio of a, b, c ages is 1:2:3.what is c's age

Answer 1

a + b + c =90

10 years before

a-10 = x
b-10 = 2x
c-10 = 3x

now
x+10 + 2x+10 + 3x+10 = 90

6x= 60

x=10

c' s age 40

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Answer 2

Answer:

The present age of c is 40 years.

Step-by-step explanation:

It is given that the sum of their ages is 90, 10 years before ratio of a, b, c ages is 1:2:3.

Let the age of three person before 10 years are x, 2x, 3x respectively.

The present age of a,b and are (x+10), (2x+10) and (3x+10) respectively.

Since the sum of their present age is 90, therefore

$(x+10)+(2x+10)+(3x+10)=90$

$6x+30=90$

$6x=60$

$x=10$

The present age of c is

$3x+10=3(10)+10=40$

Therefore the  present age of c is 40 years.