The total ages of three persons a, b, c is 90yrs, 10 yrs before ratio of a, b, c ages is 1:2:3.what is c's age
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Answered by
4
a + b + c =90
10 years before
a-10 = x
b-10 = 2x
c-10 = 3x
now
x+10 + 2x+10 + 3x+10 = 90
6x= 60
x=10
c' s age 40
Mark this answer as brainliest answer
10 years before
a-10 = x
b-10 = 2x
c-10 = 3x
now
x+10 + 2x+10 + 3x+10 = 90
6x= 60
x=10
c' s age 40
Mark this answer as brainliest answer
Answered by
0
Answer:
The present age of c is 40 years.
Step-by-step explanation:
It is given that the sum of their ages is 90, 10 years before ratio of a, b, c ages is 1:2:3.
Let the age of three person before 10 years are x, 2x, 3x respectively.
The present age of a,b and are (x+10), (2x+10) and (3x+10) respectively.
Since the sum of their present age is 90, therefore
The present age of c is
Therefore the present age of c is 40 years.
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