Question

The total area of a circle and rectangle is equal to 1166 CM square. The diameter of circle is 28 cm. What is the sum of circumference of circle and the perimeter of rectangle. If the length of rectangle is equal to 25 CM

Answer 1

Answer:

182cm

Step-by-step explanation:

Area of circle = πr2

= 227×14×14=616sq.cm

∴ Area of rectangle = 1166 - 616

= 550 sq.cm

Breadth of rectangle

= 55025=22cm

∴ Circumference of circle

= π× diameter

= 227×28=88cm

perimeter of rectangle  

= 2 (length + breadth)  

= 2 (25 + 22) = 94 cm.  

Required sum = 88 + 94  

= 182 cm.

Answer 2

HEY Buddy....!! here is ur answer

Given that : Diameter of circle = 28 cm => Radius = 28/2 = 14 cm

Length of the rectangle = 25 cm

According to the question :

πr²+(l×b) = 1166 cm² ( where, b = breadth of rectangle)

$\frac{22}{7} \times 14 \times 14 + 25 \times b = 1166 \\ \\ = > 616 + 25 \times b = 1166 \\ \\ = > 25 \times b = 550 \\ \\ = > b = \frac{550}{25} = 22 \: cm$

Now,

circumference of circle+perimeter of rectangle

=> 2πr + 2(l+b)

$= > 2 \times \frac{22}{7} \times 14 + 2(25 + 22) \\ \\ = >88 + 94 \\ \\ = > 182 \: cm$

I hope it will be helpful for you...!!

THANK YOU ✌️✌️