The total area of four walls of a room is 660 m and the length is twice its width if the height of the room is 11 m then the area of its ceiling is
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H=11m
L=20m
B=10m
A =20×10=200m^2
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Surface area=2(l+b)h
Let length be x and therefore breadh is twice then b=2x
Height =11m
2*(x+2x)*11=660
22*3x=660
66x=660
x=10
Therfore L=10 and breadth =20
Then ceiling =l*b
10*20=200
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