The total area of the four walls of a hall is 343 sq.m.its height is 7m.if the floor of the hall is in the shape of a square,the area of the floor is
Answers
Answered by
11
hey mate
here is your answer
perimeter of base * height=343
perimeter of base*7=343
perimeter of base=343/7
=49
hence
area of the base=(49/4)²
=2401/16
=150.0625
here is your answer
perimeter of base * height=343
perimeter of base*7=343
perimeter of base=343/7
=49
hence
area of the base=(49/4)²
=2401/16
=150.0625
vineetjain678:
I doubt why did you divide 2401/16 how
1****
see the area of the base is square
so it has equal sides
Yes but why did you divide
because the perimeter was 49
so to calculate it each side we divide it by 4
But they asked area not length of side
And area is s×s not 4×s
where did i multiply 4*s
Answered by
4
Let the side of the square floor be x
Then , h= 7 m
Area of one wall be 7×x= 7x
Area of four wall =7x+7x+7x+7x= 343
X= 12.25m
Now area of square is side square
So , x square
12.25×12.25= 150.06m(approximate)
Similar questions