Question

The total area of the glass window pane is 0.5 m^2. Calculate how much heat is conducted per hour through the glass window pane if the thickness of the glass is 6mm, the temperature of the inside is 23°C end of the outside surface is 2°C. Thermal conductivity of glass is 1 W/m/K. ​

Answer 1

Answer:

$\boxed{\sf Heat \ conducted \ through \ the \ plain \ glass \ window \ (Q) = 6.3 \ MJ}$

Given:

Total area of plain glass window (A)= 0.5 $\sf m^{2}$

Thickness of glass window (d) = 6 mm = $\sf 6 \times 10^{-3} \ m$

Temperature of inside surface ($\sf T_2$) = 23°C = 296 K

Temperature of outside surface ($\sf T_2$) = 2°C = 275 K

Thermal conductivity of glass (K) = 1 W/mK

Time (t) = 1 hour = 3600 seconds

To Find:

Heat conducted through the plain glass window (Q)

Explanation:

Formula:

$\boxed{\bold{\sf Q= \frac{KA(T_2-T_1)t}{d}}}$

Substituting values of K, A, $\sf T_2,T_1$, t & d in the equation:

$\sf \implies Q=\frac{1 \times 0.5 (296-275) 3600}{6 \times 10^{-3}}$

$\sf \implies Q=\frac{ 0.5 \times 21 \times 3600}{6 \times 10^{-3}}$

$\sf \implies Q=\frac{ 37800}{6 \times 10^{-3}}$

$\sf \implies Q=\frac{6300}{ 10^{-3}}$

$\sf \implies Q=6300\times 10^{3}$

$\sf \implies Q=6.3\times 10^{6} \ J$

$\sf \implies Q=6.3 \ MJ$

∴

Heat conducted through the plain glass window (Q) = 6.3 MJ