the total binding energy of 58^Ni is 508 MeV. what is its binding energy per nucleon?
Answers
Answered by
1
it's binding energy per nucleon is 8.76 MeV
given, Total binding energy of 58^Ni is 508 MeV.
we know, binding energy per nucleon = binding energy/atomic mass no
[ no of nucleon means sum of number of protons and neutrons. and we know, sum of number of protons and neutrons = mass no . so, no of nucleons = atomic mass no ]
so, binding energy per nucleon of Ni = 508/58
= 8.76 MeV/nucleon
also read similar questions : The binding energy per nucleon of is and that of is . The energy (in MeV) required to remove a neutron from is
https://brainly.in/question/3424952
THE MASS DEFECT FOR THE NUCLEUS OF HELIUM IS 0.0303amu .
WHAT IS THE ...
https://brainly.in/question/5890402
Similar questions
Math,
5 months ago
Math,
5 months ago
Computer Science,
10 months ago
Computer Science,
10 months ago
Political Science,
1 year ago
Chemistry,
1 year ago