Chemistry, asked by waghdhanashree99, 10 months ago

the total binding energy of 58^Ni is 508 MeV. what is its binding energy per nucleon?​

Answers

Answered by abhi178
1

it's binding energy per nucleon is 8.76 MeV

given, Total binding energy of 58^Ni is 508 MeV.

we know, binding energy per nucleon = binding energy/atomic mass no

[ no of nucleon means sum of number of protons and neutrons. and we know, sum of number of protons and neutrons = mass no . so, no of nucleons = atomic mass no ]

so, binding energy per nucleon of Ni = 508/58

= 8.76 MeV/nucleon

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