Question

The total binding energy per nucleon of an alpha particle is 7 MeV, and that the energy
release in the reaction d + d → α is 23.6 MeV, then find the total binding energy of a
deuteron.

Answer 1

Answer:

The nuclear reaction is,

1

H

2

+

1

H

2

→

2

He

4

+Q

Total binding energy of helium nucleus

=4×7=28 MeV

Total binding energy of each deuteron

=2×1.1=2.2 MeV

Hence, energy released when two deuteron fuse to form helium,

=28−2×2.2=28−44=23.6 MeV