Question

The total charge entering the terminal is given by q = 5tsin(4πt) coulomb calculate the current at t = 0.5 second.

Answer 1

Answer:

Current at t = 0.5 sec is 10π or 31.4 Ampere.

Explanation:

q = 5t sin(4πt)

Current is obtained by differentiating the charge with respect to time. That is, Current = dq/dt

i = dq/dt = 5sin(4πt) + 5t*4πcos(4πt)

i = 5sin(4πt) + 20πtcos(4πt)

Current at t = 0.5 sec is,

i = 5sin(4π/2) + (20π/2)*cos(4π/2)

i = 5sin(2π) + 10π*cos(2π)

i = 0 + 10π*(1)

i = 10π Ampere.

i = 31.4 Amperes