The total cost of 3 tables and 2 chairs 1850.if table cost 75 more than chair. Find price of each
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Answered by
3
3x+2y=1850{chair x and table y}.....1
x=y+75
x-y=75.....2
bas is equation ko solve kar lo ans mil jayega
x=y+75
x-y=75.....2
bas is equation ko solve kar lo ans mil jayega
Answered by
15
ANSWER
__________
Let the cost of one chair be x.
Let the cost of one table be x + 75.
Cost of 2 chairs = 2x
Cost of 3 tables = 3(x + 75)
2x + 3x + 225 = 1850
5x + 225 = 1850
5x = 1850 - 225
5x = 1625
x = 1625/5
x = 325
Chairs cost = 2x = 2 x 325 = 650
Tables cost = 3(x + 75) = 3x + 225 = 3 x 325 + 225 = 1200
_____________________________________________________________
#hope this helps u ...
#Thnx...
__________
Let the cost of one chair be x.
Let the cost of one table be x + 75.
Cost of 2 chairs = 2x
Cost of 3 tables = 3(x + 75)
2x + 3x + 225 = 1850
5x + 225 = 1850
5x = 1850 - 225
5x = 1625
x = 1625/5
x = 325
Chairs cost = 2x = 2 x 325 = 650
Tables cost = 3(x + 75) = 3x + 225 = 3 x 325 + 225 = 1200
_____________________________________________________________
#hope this helps u ...
#Thnx...
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