the total cost of 3 tables and 2 chairs is rs 745.if one table cost rs 40 more than one chair,find the price of each.s solve in method
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Let the cost of one chair be x
therefore, the cost of one table would be x+40,
Now, according to question
3(x+40) + 2x = 745
= 3x + 120 + 2x = 745
= 5x = 745 - 120
= 5x = 625
= x = 625/5= 125
Cost of one chair = 125
Cost of one table = 125+40= 160
therefore, the cost of one table would be x+40,
Now, according to question
3(x+40) + 2x = 745
= 3x + 120 + 2x = 745
= 5x = 745 - 120
= 5x = 625
= x = 625/5= 125
Cost of one chair = 125
Cost of one table = 125+40= 160
bindutiwari:
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