the total cost of 3 tables and 2 chairs is rupees 1850. if a table costs rupees 75 more than a chair, find the price of each
Answers
Answered by
40
Hi....!!
Let's solve it.....
Cost of a chair = x
Cost of a table = x+75
The total price paid = 1850
x+x+x+75+x+75+x+75=1850
5x+225=1850
5x= 1850-225
5x = 1625
x =1625/5
x = 325
Cost of chair = x = 325rs
Cost of table = x+75 = 400rs
Hope this helps....!!
^_^
Let's solve it.....
Cost of a chair = x
Cost of a table = x+75
The total price paid = 1850
x+x+x+75+x+75+x+75=1850
5x+225=1850
5x= 1850-225
5x = 1625
x =1625/5
x = 325
Cost of chair = x = 325rs
Cost of table = x+75 = 400rs
Hope this helps....!!
^_^
Answered by
17
Let the table = x+75
Let the chair = x
from the equation we can know that
3(x+75)+2x = 1850
3x + 225 + 2x = 1850
5x = 1850 - 225
5x = 1625
x = 1625/5
x = 325 ⇒ chair = 325, table = x + 75
table = 325 + 75
= 400 r.s
Let the chair = x
from the equation we can know that
3(x+75)+2x = 1850
3x + 225 + 2x = 1850
5x = 1850 - 225
5x = 1625
x = 1625/5
x = 325 ⇒ chair = 325, table = x + 75
table = 325 + 75
= 400 r.s
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