Question

The total cost of 3 tables and 5 chairs is 6300rupees.if the table costs 500 rupees more than the chair ,find the cost of 3 tables and the cost of 5 chairs

Answer 1

Answer:

Let us assume that the cost of one chair is 'x'

So, from the question since table costs rupees 500 more than the chair

Price of one Table = x+500

Now, From the question - the total cost of 3 tables and 5 chairs is rupees 6300

3(x+500) + 5x = 6300

3x + 1500 + 5x = 6300

8x + 1500 = 6300

8x = 6300 -1500

x = 6300 - 1500 = 4800 = 600

8 8

Price of one chair (x) = 600

Price of one Table = x+500 = 600 +500 = 1100

Now, we have to find the cost of 3 tables and the cost of 5 chairs

Price of one chair = 600

• Price of 5 such chairs = 5 x 600 3000

Price of one Table = 1100

• Price of 3 such tables = 3 ×

1100 = ₹ 3300

Answer 2

Given data : The total cost of 3 tables and 5 chairs is Rs 6300. The table cost is Rs 500 more than the chair.

Solution : A/C to question;

Let, cost of a tabes be x and cost of a chairs be y.

Now, a/c to given data; {The total cost of 3 tables and 5 chairs is Rs 6300.}

• 3x + 5y = 6300 ----{1}

and {the table cost. is Rs 500 more than the chair}.

• x = y + 500 ----{2}

Form {2}

Put value of x in eq. {1}

➜ 3x + 5y = 6300

➜ 3 ( y + 500) + 5y = 6300

➜ 3y + 1500 + 5y = 6300

➜ 3y + 5y + 1500 = 6300

➜ 8y + 1500 = 6300

➜ 8y = 6300 - 1500

➜ 8y = 4800

➜ y = 4800/8

➜ y = 600 ----{3}

Now, put value of y in eq. {2}

➜ x = y + 500

➜ x = 600 + 500

➜ x = 1100 ----{4}

From {3} and {4},

• Cost of one tabe = Rs 1100

and

• Cost of one chair = Rs 600

Now,

• Cost of 3 tabes = 3x = 3 * 1100 = Rs 3300

and

• Cost of 5 chairs = 5y = 5 * 600 = Rs 3000

Answer : Hence the cost of 3 tabes and the cost of 5 chairs are Rs 3300 and Rs 3000 respectively.

{Verification : Put value of x and y in eq. {1}

➜ 3x + 5x = 6300

➜ 3 * 1100 + 5 * 600 = 6300

➜ 3300 + 3000 = 6300

➜ 6300 = 6300

Hence it verified.}

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