Question

the total cost of 3 tables and 5 chairs is ruppes 6300. study table costs ruppes 500 more than the chair, find the cost of 3 tables and the cost of 5
chairs?​

Answer 1

                    ◦ ❖ SOLUTION ❖ ◦

Let us assume that the cost of one chair is 'x'

So, from the question since table costs rupees 500 more than the chair

Price of one Table = x+500

Now , From the question - the total cost of 3 tables and 5 chairs is rupees 6300

$\implies$ 3(x+500) + 5x = 6300

$\implies$ 3x + 1500 + 5x = 6300

$\implies$ 8x + 1500 = 6300

$\implies$ 8x = 6300 -1500

∴

$x = \dfrac{6300-1500}{8} = \dfrac{4800}{8} = 600$

Price of one chair (x) = ₹ 600

Price of one Table = x+500 = 600 + 500 = ₹1100

Now, we have to find the cost of 3 tables and the cost of 5 chairs

∵ Price of one chair = ₹ 600

$\red\bigstar$ Price of 5 such chairs = 5 × 600 = ₹ 3000

∵ Price of one Table =  ₹ 1100

$\red\bigstar$ Price of 3 such tables = 3 × 1100 =  ₹ 3300

Answer 2

Correct Question

☛ The total cost of 3 tables and 5 chairs is rupee 6300.If the table costs rupee 500 more than the chair,find the cost of 3 tables and the cost of 5 chairs.

GiveN:-

☛ Total cost of 3 tables and 5 chairs is rupee 6300.The cost of table is rupee 500 more than that of the chair.

To FinD:-

☛ The cost of 3 tables and the cost of 5 chairs.

UnknowN:-

☛ Let the cost of one chair be c.

The cost of one table would be c + 500.

EquatioN:-

Since the total cost of 3 tables and 5 chairs is rupee 6300.

3( c + 500) + 5c = 6300

SolutioN:-

$\sf{3c + 1500 + 50 = 6300} \\ \sf{8c + 1500 = 6300} \\ \sf{8c + 1500 - 1500 = 6300 - 1500} \\ \sf{8c = 4800} \\ \sf{{ { \cancel \frac{8c}{8}}}} = \frac{4800}{8} \\ \sf{c = 600}$

The cost of a chair is rupee 600 and the cost of a table is rupee 600 + rupee 500 = rupee 1100

Hence,the cost of 3 tables is 3x rupee 1100 = 3300 and the cost of 5 chair is rupee 600 = ,3000.

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