Question

the total cost of 4 kg of apples and 6 of orange is Rs 570 if the cost of 3 kg of Apples in the same as the cost of 5 kg of orange find the rate of the cost apples and oranges​

Answer 1

Answer:

1 kg apple cost = X= Rs 75

1 kg orange cost = Y = Rs 45

Step-by-step explanation:

Assume

1 kg apple cost = X

4KG apple cost  = 4X

1 kg orange cost = Y

6kg orange cost = 6Y

4X + 6Y = 570

3kg of apple = 5kg of orange

i.e.

3X = 5Y

X= 5/3Y

NOW

4X + 6Y = 570

X = 5/3 Y

4(5/3Y)+ 6Y = 570

20/3Y+6Y = 570

(20 Y +18 Y)/3 = 570

(38/3)Y=570

38Y= 570*3

38Y= 1710

Y = 45

NOW

X = 5/3 Y

Y = 45

X = (5/3)*45

X = 75

1 kg apple cost = X= Rs 75

1 kg orange cost = Y = Rs 45

Answer 2

Answer:

Therefore, the required rate of cost of apples is Rs 75 and the rate of cost of oranges is Rs 45.

Step-by-step explanation:

Let the cost of 1kg of apple be Rs'x' and the cost of 1kg of orange be Rs'y'.

According to the question,

Condition I,

The total cost of 4kg of apples and 6 kg of oranges is Rs. 570.

or,4x+6y=570

or,4x=570−6y

or,x=570−6y4 - (i)

Condition II,

The cost of 3kg of apples is the same as the cost of 5kg of oranges.

or,3x=5y - (ii)

Now,

Put the value of x from equation (i) into equation (ii), we get,

or,3(570−6y4)=5y

or,3(570−6y)4=5y

or,1710−18y=5y×4

or,1710=20y+18y

or,1710=38y

or,y=171038

∴y=45

Again,

Put the value of y in equation (i), we get,

or,x=570−6×454

or,x=3004

∴x=75

So, (x,y) = (75,45)

Therefore, the required rate of cost of apples is Rs 75 and the rate of cost of oranges is Rs 45.