Question

The total cost of 6 tables and 4 chairs is Rs. 1250. If one table costs Rs. 30
more than one chair, find the price of each table and chair respectively.​

Answer 1

Answer:

Let us assume that the cost of one chair is 'x'.

Let us assume that the cost of one table is 'y'.

CASE - 1

It is said in the question that  total cost of 6 tables and 4 chairs is Rs. 1250.

$\implies$ 6x + 4y = 1250 $\longrightarrow$ (1)

CASE - 2

It is also said that one table costs Rs. 30 more than one chair.

$\implies$ x + 30 = y

$\implies$ x = y - 30 $\longrightarrow$ (2)

Now, let us substitute x = y - 30 from (2) in (1).

$\implies$ 6(y - 30) + 4y = 1250

$\implies$ 6y - 180 + 4y = 1250

$\implies$ 10y - 180 = 1250

$\implies$ 10y = 1250 + 180

$\implies$ 10y = 1430

$\implies \sf y = \dfrac{1430}{10}$

Cost of one table (y) = ₹143.

Now,let us substitute , y =  143 in (2).

$\implies$ x = 143 - 30 = ₹113

Cost of one chair = ₹113