Math, asked by pleasehelp64, 9 months ago

The total cost of a dozen apples and half dozen oranges cannot exceed ₹180. The cost of each orange cannot exceed ₹5. Find the minimum possible cost of each apple

Answers

Answered by rajeswar
9

Answer:

Hey Champ Lemme Help You..............

Step-by-step explanation:

Let the cost of 1 apple be 'x'

Let the cost of 1 orange be 'y'

According to the question

Dozen Apples +1/2 Dozen Oranges < Rs.180.

ATQ

12X+6Y < 180............ Let it be equation 1

If we simplify 2X+Y < 30

As given cost of each orange cannot exceed Rs.5

Therefore, Y < 5.

So, Minimum cost of each apple

2X > 25

X > 25/2

X=12.5

Hence cost of each apple is Rs.12.5.

Hope it helps if it did please mark it as the brainiest answer

Answered by mahi946535
5

Answer:

Let the cost of 1 apple be 'x'

Let the cost of 1 orange be 'y'

According to the question

Dozen Apples +1/2 Dozen Oranges < Rs.180.

ATQ

12X+6Y < 180............ Let it be equation 1

If we simplify 2X+Y < 30

As given cost of each orange cannot exceed Rs.5

Therefore, Y < 5.

So, Minimum cost of each apple

2X > 25

X > 25/2

X=12.5

Hence cost of each apple is Rs.12.5.

Step-by-step explanation:

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