Question

The total cost of carpeting a floor at the rate of Rs.75 per sq.m. is Rs.6000. If the breadth of the floor is 16m, find its perimeter.

Answer 1

Answer:

Step-by-step explanation:

Length=10 m

Breadth=b m

Total Area =(10×b)m sq.

Cost of 1 m sq.=75

Cost of flooring= (75×10b)

6000= 75×10b

\begin{gathered}b = \frac{6000}{75 \times 10} \\ = \frac{6000}{750} \\ = 8m\end{gathered}

b=

75×10

6000

=

750

6000

=8m

Therefore, the breadth =8m

Step-by-step explanation:

hope it is helpful

Answer 2

Answer:

Correct option is

B

7.5m

Cost of flooring per square meter = Rs.8.50

⇒ Total cost of flooring of room = Rs.510

∴ Area of the room =

8.50

510

=60m

2

⇒ Area of the room = l×b

⇒ 60=8×b

∴ b=

8

60

=7.5m.

∴ Breadth of the rioom is 7.5m.