Question

The total cost of fencing a rectangular field at the rate of rupees 31 per metre is rupees 2914, if it's length is 25 metre find the breadth

Answer 1

Answer:

Perimeter of a Rectangle = 2( Length + Breadth )

Perimeter = Rs 2914 / Rs 31 /metre

= 94m

According to the Question,

2( 25+ Breadth ) = 94m

50 + 2 * Breadth = 94m

2 * Breadth = 94m - 50m

2 * Breadth = 44m

Breadth = 44m/2

= 22m

Breadth = 22m

Verification:- Scene 1

94m = 2( 25 + 22 )m

=50m + 44m

= 94m

94m = 94m

LHS = RHS

Hence, Verified

Verification:- Scene 2

Rs 2914 = Rs ( 94 * 31 )

= Rs 2914

Rs 2914 = Rs 2914

LHS = RHS

Hence, Verified

Answer 2

Given :-

• Cost of fencing a rectangular field at the rate of Rs. 31 per m is Rs. 2914
• Length of that rectangular field is 25 m

To Find :-

• Breadth of that rectangular field

Solution :-

~ Here we're given the cost of fencing and the cost of fencing per m and we know that :

Cost of fencing = Perimeter × Cost per m

$\sf \implies 2914 = 31 \times Perimeter$

$\sf \implies Perimeter = \dfrac{2914}{31}$

$\sf Perimeter = 94 \; cm$

~ We know the length and the perimeter so we can find the breadth by putting the values

Perimeter of rectangle = 2( l+b )

Where ,

• l is length
• b is breadth

$\sf \implies 94 = 2 (25+b)$

$\sf \implies 25 + b = \dfrac{94}{2}$

$\sf \implies 25 + b = 47$

$\sf \implies b = 47 - 25$

$\sf \implies b = 22\; m$

∴ Breadth of the rectangular field is 22 m

More Formulas :-

Perimeter = 2 ( l + b )

Area = l × b

$\sf Length = \dfrac{Area}{Breadth}$

$\sf Breadth = \dfrac{Area}{Length}$

$\sf Diagonal = \sqrt{l^{2} +b^{2} }$