Question

the total cost of flooring the room at a rate of rupees 6.50 per square metre is rupees 2600 if the width of the room is 10 M find the length​

Answer 1

Given :

• Total cost of flooring = Re.2600
• Rate of flooring = Rs.6.50 per m²
• Width of room = 10 m

To Find :

• Length of Room = ?

Solution :

${\orange{✇}}$ Formula Used :

• ${\underline{\boxed{\red{\sf{ Area = Length \times Breadth }}}}}$

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${\orange{✇}}$ Calculating the Area of Room :

${\longmapsto{\qquad{\sf{ Area{\small_{(Room)}} = \dfrac{Total \; Cost}{Rate} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Area{\small_{(Room)}} = \dfrac{2600}{6.50} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Area{\small_{(Room)}} = \dfrac{2600 \times 10}{650} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Area{\small_{(Room)}} = \dfrac{26000}{650} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Area{\small_{(Room)}} = \cancel\dfrac{26000}{650} }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\color{darkblue}{\pmb{\frak{ Area \; of \; Room = 40 \; {m}^{2} }}}}}}}}$

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${\orange{✇}}$ Calculating the Length of Room :

${\dashrightarrow{\qquad{\sf{ Area = Length \times Breadth }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ 40 = Length \times 10 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ \dfrac{40}{10} = Length }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ \cancel\dfrac{40}{10} = Length }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\pink{\pmb{\frak{ Length \; of \; Room = 4 \; m }}}}}}}}$

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${\orange{✇}}$ Therefore :

❛❛ Length of the Room is 4 m . ❜❜

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