The total cost of three prizes is 900. If the value of second prize is 1/2 of the first and the value of 3rd prize is 3/4 of the first prize, find the value of first prize
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Answer:
value of first price is 400
Step-by-step explanation:
let x,y and z be the 3 prize value.
given, y = (1/2)*x => x = 2y ----- (1)
also, z = (3/4)*x => 3x = 4z
ie., 3(2y) = 4z
=> 3y = 2z
=> z = (3/2)y --------- (2)
given, x+y+z = 900
=> 2y + y + (3/2)y = 900 ( by (1) and (2) )
=> 3y + (3y/2) = 900
=> (6y +3y)/ 2 = 900
=> 9y = 2*900
=> y = 2*100
=> y = 200
=> value of first price , x = 2y ( by (1) )
=> x = 2(200)
=> x = 400
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