The total cost of two almirahs and four table
fans is *7,516. If the cost of the almirah is 1929
more than that of the fan, find the price of
each item.
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Answer:
The Cost of Fan = 609.6 rupees
The Cost of Almirah = 2538.6 Rupees
Step-by-step explanation:
Let's suppose,
Cost of fan = y
Cost of Almirah = x
Given that, The total cost of two almirahs and four table fans is 7,516 rupees
Thus, 2x+4y=7516.
Also, The cost of the almirah is 1929 more than that of the fan.
Thus x=1929+y.
Substitute x value in 2x+4y=7516 equation.
∴ 2(1929+y) + 4y = 7516
3858+2y+4y = 7516
3858+6y = 7516
⇒6y = 7516-3858
= 3658
⇒y = 3658/6= 609.6
∴ The value of y = 609.6 rupees
And substitute this y value in the equation x=1929+y
∴ x = 1929 + 609.6 = 2538.6 Rupees.
Hence, The cost of one fan is 609.6 rupees and the cost of one almirah is 2538.6 rupees
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