Question

the total cost price of two cell phones is rupees 30000 if one of them is sold at a profit of 15% and the other at a loss of 24% there will be a loss of 0.6 % as a whole find the cost price of each​

Answer 1

Step-by-step explanation:

Let there be two mobiles X and Y, for X,

S.P= 6000 (Given)

Profit%=20%

Then CP= (6000x100)/120=5000

Similiarly, for Mobile Y

S.P= 6000 (Given)

Loss%=25%

Then CP= (6000x100)/75= 8000

Total Cost Price, i.e., Total CP= 8000+5000=13000

Total Selling Price, i.e., Total SP= 6000+6000=12000

Since S.P< C.P loss has occured.

Also,

Loss% = [(C.P-SP)/CP]x100

Thus,

Loss%=(1000/13000)x100=7.692%

Answer 2

Answer:

18000 and 12000

explanation

let the cost of first cell phone be x

and other be 30000- x

cost of first cell phone = x

profit = 15%

= x + 15/100 × x

= x + 15x/100

cost of 2nd cell phone= 30000- x

loss = 24%

= x - 24/100 × 30000 - x

= x - 7200 - x

there is a loss of 0.6% = 0.6/100×30000=180

30000- 180 = 29820

According to question

x+ 15x/100+ x - 7200 - x = 29820

I don't know after that