Physics, asked by skgamingtamil, 9 months ago

The total distance between four
consecutive crests of a transverse wave
is 6m. What is the wavelength of the
wave.

Answers

Answered by AnkitBhardwaj420
3

Answer:

The distance between two successive crests is 1

1

wavelength,λ

λ

. Thus in a time of 1

1

period, the wave will travel 1

1

wavelength in distance. Thus the speed of the wave,

v

v

, is:

v= distance travelled

time taken =

λ

T

v=distance travelledtime taken=λT

However,f=

1

T

f=1T

. Therefore, we can also write:

v

=

λ

T

=λ⋅

1

T

=λ⋅f

v=λT=λ⋅1T=λ⋅f

We call this equation the wave equation. To summarise, we have that

v=λ⋅f

v=λ⋅f

where

v=

v=

speed in

m⋅s −1

m·s−1

λ=

λ=

wavelength in m

m

f=

f=

frequency in Hz

Hz

Wave equation:

v=f⋅λ

v=f⋅λ

or

v=

λ

T

v=λT

Answered by pastimeplays
4

Answer:

1.5m

Explanation:

The wavelength of a wave can be defined as the distance between any two consecutive crests.

Since the distance is between 4 crests, we can say that 3 waves have been covered,

3 waves = 6 m

1 wave = 6 ÷ 3 = 2m

Comment if you have any doubts

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