Question

The total energy of a electron in the first excited state of hydrogen atom in about 3.4ev.What is the potential energy

Answer 1

Potential energy (U) of the electron is equal to the negative of twice of its kinetic energy.

U = −2 K

= − 2 × 3.4 = − 6.8 eV

Hence, the potential energy of the electron in the given state is − 6.8 eV.

Answer 2

Answer:

potential energy is 6.8 eV.

Explanation:

Given,

The total energy of a electron in the first excited state of hydrogen atom in about 3.4 eV.

We know, Potential energy  of the electron is equal to the negative of twice its kinetic energy. Also, Kinetic energy is equal to the negative of the total energy of an electron.

hence, K.E = - 3.4 eV

So,Total Energy = K.E + P.E

3.4 eV = -3.4 eV + P.E

or, P.E = 6.8 eV

Therefore, potential energy is 6.8 eV.