Question

The total energy of a particle of mass 2.5 gm
performing linear S.H.M. is 1.25 x 10-5 J. Find
the maximum velocity of the particle.​

Answer 1

Answer:

KE = 1/2MV^2

1/2 MV^2 = 1.25 × 10^-5

V = 10^-1m/sec

Thanks for Reading